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Sagot :
EXPLANATION:
Given;
We are told that Janet, Li Na and Katie all have a total of 68 beads.
We are also told that;
(i) Janet has 3 times as many beads as Li Na
(ii) Katie has 5 more beads than Janet.
Required;
We are required to find out how many beads Katie has.
Step-by-step solution;
From the conditions given, Janet has 3 times as many beads as Li Na. That means if Li has an y number of beads, Janet's would be times 3.
Therefore, if Li Na is L and Janet is J, then it means;
[tex]\begin{gathered} Li\text{ }Na=l \\ Janet=3l \end{gathered}[/tex]Also we are told that Katie has 5 more beads than Janet. That means, if Katie is K, then;
[tex]\begin{gathered} Janet=3l \\ Katie=3l+5 \end{gathered}[/tex]Bear in mind that they all have a total of 68 beads. Hence, we add up their beads as follows;
[tex]\begin{gathered} LiNa+Janet+Katie=68 \\ l+3l+3l+5=68 \end{gathered}[/tex][tex]7l+5=68[/tex]Subtract 5 from both sides;
[tex]7l+5-5=68-5[/tex][tex]7l=63[/tex]Divide both sides by 7;
[tex]\frac{7l}{7}=\frac{63}{7}[/tex][tex]l=9[/tex]This means Li Na has 9 beads. If Katie's bead is given by the expression 3l + 5, then she will have;
[tex]\begin{gathered} Katie=3l+5 \\ Katie=3(9)+5 \\ Katie=18+5 \\ Katie=23 \end{gathered}[/tex]ANSWER:
Katie has 23 beads.
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