Answered

At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

Determine the equation of the line that passes through the point (-1, 2) and isperpendicular to the line y = -2.

Determine The Equation Of The Line That Passes Through The Point 1 2 And Isperpendicular To The Line Y 2 class=

Sagot :

[tex]y=-\frac{1}{2}x+\frac{3}{2}[/tex]

1) In this question, let's find the equation, using the point-slope formula:

[tex](y-y_0)=m(x-x_0)[/tex]

2) Notice that since we want a perpendicular line we can write a perpendicular line to y=2, as x=-1/2 for -1/2 is the opposite and reciprocal to 2 (the necessary condition to get a perpendicular line).

So, the slope of that perpendicular line is -1/2

3) Let's plug into that Point-Slope formula, the slope m= -1/2 and the point:

[tex]\begin{gathered} (y-2)=-\frac{1}{2}(x+1) \\ y-2=-\frac{1}{2}x-\frac{1}{2} \\ y=-\frac{1}{2}x-\frac{1}{2}+2 \\ y=-\frac{1}{2}x+\frac{3}{2} \end{gathered}[/tex]

4) Thus, the answer is:

[tex]y=-\frac{1}{2}x+\frac{3}{2}[/tex]

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We appreciate your time. Please come back anytime for the latest information and answers to your questions. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.