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can u help me with this by using inverse trig.ratios. Find angle A and angle B.

Can U Help Me With This By Using Inverse Trigratios Find Angle A And Angle B class=

Sagot :

The hypotenuse is 39 because is opposite to the angle of 90 degrees.

So, angle A is given by

[tex]\measuredangle A=\sin ^{-1}\frac{7}{39}[/tex]

Then, we have

[tex]\measuredangle A=\sin ^{-1}(0.17948)[/tex]

which gives

[tex]\measuredangle A=10.339\text{ degre}es[/tex]

Now, angle C is equal to 90 degrees and angle B is given by

[tex]\begin{gathered} \measuredangle B=\cos ^{-1}(\frac{7}{39}) \\ \measuredangle B=\cos ^{-1}(0.17948) \\ \measuredangle B=79.66\text{ degr}ees \end{gathered}[/tex]

Therefore, the answer is

[tex]\begin{gathered} \measuredangle A=10.339\text{ degre}es \\ \measuredangle B=79.669\text{ degre}es \\ \measuredangle C=90\text{ degre}es \end{gathered}[/tex]