Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
Hello
To solve this question, i will use quadratic formula; however, there are other methods we can use to solve this question.
Step 1
Collect like terms
[tex]\begin{gathered} 2x^2+3x=9x+2 \\ 2x^2+3x-9x-2=0 \\ 2x^2-6x-2=0 \end{gathered}[/tex]A standard quadratic equation can be represented as
[tex]\begin{gathered} ax^2+bx+c=0 \\ a=2,b=-6,c=-2 \end{gathered}[/tex]The quadratic equation is given as
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]Therefore,
[tex]\begin{gathered} x=\frac{-(-6)\pm\sqrt[]{(-6)^2-4(2)(-2)}}{2\times2} \\ x=\frac{6\pm\sqrt[]{36+16}}{4} \\ x=\frac{6\pm\sqrt[]{52}}{4} \\ x=\frac{6\pm7.2}{4} \\ x=\frac{6+7.2}{4}=3.3 \\ or \\ x=\frac{6-7.2}{4}=-0.3 \end{gathered}[/tex]From the calculations above, the value of x is either 3.3 or -0.3
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.
