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Re-arrange this vertex equation y = 2 (x + 1)2 - 6 in standard form?

Sagot :

When we have a quadratic equation, we can have it in vertex and standard form.

The vertex form comes in the form:

[tex]y=a\mleft(x-h\mright)^2+k[/tex]

The standard form comes in the form:

[tex]y=ax^2+bx+c[/tex]

Converting to/from either simply requires some manipulations via expansion of the bracket as will be seen.

[tex]\begin{gathered} y=2(x+1)^2-6 \\ y=2(x^2+2x+1)-6 \\ y=2x^2+4x+2-6 \\ y=2x^2+4x-4 \end{gathered}[/tex]

Hence, we have our standard form.

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