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in a particular hospital, newborn babies were delivered yesterday. here are their weights (in ounces). 121 ,101 ,97 121,124 ,112 assuming that these weights constitute an entire population, find the standard deviation of the population. round your answer to two decimal places.

Sagot :

The standard population formula is:

[tex]\sigma=\sqrt[]{\frac{\sum ^{}_{}(x_{}-\mu)^2}{n}}[/tex]

where

x is the data points

μ is the mean of the data

and n is the number of data points

The mean is computed as follows:

[tex]\mu=\frac{\Sigma x}{n}[/tex]

In this case, the mean is:

[tex]\mu=\frac{121+101+97+121+124+112}{6}=\frac{676}{6}=112.67[/tex]

Then, the standard deviation of the population is:

[tex]\begin{gathered} \sigma=\sqrt[]{\frac{(121-112.67)^2+(101-112.67)^2+(97-112.67)^2+(121-112.67)^2+(124-112.67)^2+(112-112.67)^2}{6}} \\ \sigma=\sqrt[]{\frac{69.39+136.19+245.55+69.39+128.37+0.045}{6}} \\ \sigma=\sqrt[]{108.22} \\ \sigma=10.4 \end{gathered}[/tex]