Answered

Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

A 3.0kg cat and a 14kg dog exert a force of gravity on each other equal to 1.12 x 10^-10 N. how far apart are they

Sagot :

The expression for the gravitational force between two bodies is given by:

[tex]F=G\frac{m_1m_2}{r^2}[/tex]

where,

G: Cavendish's constant = 6.67*10-11Nm^2/kg^2

m1 = 3.0kg

m2 = 14kg

Solve the equation above for r:

[tex]\begin{gathered} r=\sqrt{\frac{Gm_1m_2}{F}} \\ r=\sqrt[]{\frac{(6.67\cdot10^{-11}\frac{Nm^2}{\operatorname{kg}^2})(3.0kg)(14kg)}{10\cdot10^{-10}N}} \\ r\approx1.67m \end{gathered}[/tex]

Hence, the distance between the dog and the car is approximately 1.67m

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.