Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
We are given the following functions
[tex]f\mleft(x\mright)=6x+7\qquad g(x)=-2x-4\qquad h(x)=-\frac{3x}{4}[/tex]We are asked to find out g(-6) and h(-12)
1. g(-6)
it simply means that we have to plug x = -6 into the function of g(x)
[tex]\begin{gathered} g(x)=-2x-4 \\ g(-6)=-2(-6)-4 \\ g(-6)=12-4 \\ g(-6)=8 \end{gathered}[/tex]Therefore, g(-6) = 8
2. h(-12)
Once again we have to plug x = -12 into the function of h(x)
[tex]\begin{gathered} h(x)=-\frac{3x}{4} \\ h(-12)=-\frac{3(-12)}{4} \\ h(-12)=\frac{36}{4} \\ h(-12)=9 \end{gathered}[/tex]Therefore, h(-12) = 9
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.