Answer:
[tex]C_2H_4[/tex]Explanation:
Here, we want to get the chemical formula for the compound
From what we have, the compound contains hydrogen and carbon only
We also were given that the molar mass is 28.06 amu
Now,we beed to get the individual atomic mass of carbon and hydrogen
From records, carbon has an AMU of 12.01
The AMU of hydrogen is 1.00794
Looking at the total value, we can see that the max possible number of atoms of carbon present is 2
Now, we need to know the number of hydrogen atoms
Let us call this n
Mathematically, we know that the AMU of the compound is the sum of the AMU of the individual atoms
Hence, we have it that:
[tex]\begin{gathered} 28.06\text{ = 2(12.01) + n(1.00794)} \\ 1.00794n\text{ = 28.06 - 24.02} \\ 1.00794n\text{ = 4.04} \\ \\ n\text{ = }\frac{4.04}{1.00794} \\ \\ n\text{ = 4} \end{gathered}[/tex]Finally, we want to write the molecular formula of the compound
The molecular formula is written with carbon first, followed by its number of atoms as subscript, then hydrogen , with its number of atoms as subscript
We have this written as:
[tex]C_2H_4[/tex]