Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
There are 2 options to get the same number, they choose 6 from both lists or they choose 8 from both lists.
Then, the probability to select 6 from the first list is:
[tex]\frac{1}{4}[/tex]Because we have 4 options ( 2, 4, 6, 8) and 1 of then is number 6. At the same way, the probability to select 6 from the second list is:
[tex]\frac{1}{3}[/tex]Because there are 3 numbers and one of them is 6.
Finally, the probability to choose 6 from both lists is the multiplication of the probabilities above, so:
[tex]P_6=\frac{1}{4}\cdot\frac{1}{3}=\frac{1}{12}[/tex]We can also calculate the probability to choose 8 from both lists as:
[tex]P_8=\frac{1}{4}\cdot\frac{1}{3}=\frac{1}{12}[/tex]Because 1/4 is the probability to choose 8 from the first list and 1/3 is the probability to select 8 from the second list.
Therefore, the probability that both numbers are the same is the sum of the probability to choose 6 from both lists and the probability to choose 8 form both lists.
[tex]\begin{gathered} P=P_6+P_8 \\ P=\frac{1}{12}+\frac{1}{12} \\ P=\frac{1}{6} \end{gathered}[/tex]Answer: b. 1/6
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.
