Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Join our Q&A platform and connect with professionals ready to provide precise answers to your questions in various areas. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

(A) How many ways can a 2-person subcommittee be selected from a committee of 8 people?

Sagot :

To solve this problem, we have to use the combination formula

[tex]C^r_n=\frac{n!}{r!(n-r)!}[/tex]

Where r represents the number of people for the subcommittee (2), and n represents the total committee (8). Replacing this information, we have

[tex]C^2_8=\frac{8!}{2!(8-2)!}=\frac{8!}{2!(6)!}[/tex]

Remember that factorials are solved by multiplying the number in a reversal way, as follows

[tex]C^2_8=\frac{8\cdot7\cdot6\cdot5\cdot4\cdot3\cdot2\cdot1}{(2\cdot1)(6\cdot5\cdot4\cdot3\cdot2\cdot1)}=\frac{40,320}{2(720)}=\frac{40,320}{1,440}=28[/tex]

Therefore, there are 28 ways to form a 2-person subcommittee from a committee of 8.