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ANSWER
The mass of hydrogen in 25g of (NH4)2S04 is 1.5152 grams
EXPLANATION
Given information
[tex]\text{ The mass of \lparen NH}_4)_2SO_4\text{ is 25g}[/tex]To find the grams of hydrogen, please follow the steps below
Step 1: Find the molar mass of (NH4)2SO4
Recall, that
The unit mass of nitrogen is 14u
The unit mass of hydrogen is 1u
The unit mass of sulfur is 32u
The unit mass of oxygen is 16u
[tex]\begin{gathered} \text{ \lparen NH}_4)_2SO_4\text{ = \lbrack\lparen14 + \lparen1}\times4)]\times2\text{ + \lparen32\rparen + \lparen4 }\times16) \\ \text{ \lparen NH}_4)_2SO_4\text{ = \lparen14 + 4\rparen}\times2\text{ + 32 + 64} \\ \text{ \lparen NH}_4)_2SO_4\text{ = 18}\times2\text{ + 32 +64} \\ (NH_4)_2SO_4\text{ = 36 +32 +64} \\ \text{ \lparen NH}_4)_2SO_4\text{ = 132 g/mol} \end{gathered}[/tex]From the calculations, the molar mass of (NH4)2SO4 is 132 g/mol
Step 2: Find the number of moles of the compound
[tex]\begin{gathered} \text{ Mole = }\frac{\text{ mass}}{\text{ molar mass}} \\ \end{gathered}[/tex]Mass = 25g
Molar mass = 132 g/mol
Substitute the given data into the formula above
[tex]\begin{gathered} \text{ Mole = }\frac{25}{132} \\ \text{ Mole = 0.1894 mol} \end{gathered}[/tex]The number of moles of (NH4)2SO4 is 0.1894 mol
Step 3: Find the moles of hydrogen in the compound
There are 8 hydrogen atoms in (NH4)2SO4
Hence, we can find the number of moles of hydrogen below
[tex]\begin{gathered} \text{ Mole of hydrogen = 8 }\times\text{ 0.1894} \\ \text{ Mole of hydrogen = 1.5152 moles} \end{gathered}[/tex]Step 4: Find the mass of hydrogen using the below formula
[tex]\text{ Mole = }\frac{mass}{\text{ molar mass}}[/tex]Recall, that the molar mass of hydrogen is 1.000 g/mol
[tex]\begin{gathered} \text{ 1.5152 = }\frac{\text{ mass}}{\text{ 1}} \\ \text{ cross multiply} \\ \text{ mass = 1.5152}\times\text{ 1} \\ \text{ Mass = 1.5152 grams} \end{gathered}[/tex]Hence, the mass of hydrogen in 25g of (NH4)2S04 is 1.5152 grams
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