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Sagot :
Answer:
-292.8J/mmol
Explanations:
Given the reaction of NaCl and NaOH expressed by the chemical equation:
[tex]6HCl+6NaOH\rightarrow6NaCl+6H_2O[/tex]Amount of heat released when one mole of strong acid reacts with one mole of the strong base is -48.8 kJ/mmol.
If 6 moles of the sample acid reacts with 6 moles of NaOH, the required enthalpy cheange is expressed as:
[tex]\begin{gathered} Amount\text{ of heat released }=6\times-48.8 \\ Amount\text{ of heat released}=-292.8kJ\text{/mmol} \end{gathered}[/tex]Hence the enthalpy change if you neutralized six moles of HCl with an equal number of moles NaOH is -292.8J/mmol
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