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Sagot :
Let x = small drinks
Let y = large drinks
3 small drinks and 2 large drinks contain 108 ounces of cola, this is:
3x + 2y = 108
A small drink contains a third as much cola as a large drink, this is:
x = 1/3y
Then, we solve the system of equations:
[tex]\begin{gathered} 3x+2y=108 \\ x=\frac{1}{3}y \end{gathered}[/tex]First, substitute x in equation 1:
[tex]3(\frac{1}{3}y)+2y=108[/tex]And solve for y:
[tex]\begin{gathered} y+2y=108 \\ 3y=108 \\ \frac{3y}{3}=\frac{108}{3} \\ y=36 \end{gathered}[/tex]Next, substitute y = 36 in x:
[tex]x=\frac{1}{3}y=\frac{1}{3}(36)=12[/tex]Answer:
Small drinks: 12 ounces of cola
Large drinks: 36 ounces of cola
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