Answered

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Consider this system of linear equations:y = 4/5x - 3y = 4/5x + 1Try solving the system of equations algebraically and describe the result you get.

Consider This System Of Linear Equationsy 45x 3y 45x 1Try Solving The System Of Equations Algebraically And Describe The Result You Get class=

Sagot :

the system has not solution

Explanation

[tex]\begin{gathered} y=\frac{4}{5}x-3 \\ y=\frac{4}{5}x+1 \end{gathered}[/tex]

Step 1

to solve this we can use, Equalization, It consists in isolating from both equations the same unknown factor to be able to equal both expressions, obtaining one equation with one unknown factor.

[tex]\begin{gathered} \text{set y=y} \\ so \\ \frac{4}{5}x-3=\frac{4}{5}x+1 \\ \text{subtract 4/5 of x in both sides} \\ \frac{4}{5}x-3-\frac{4}{5}x=\frac{4}{5}x+1-\frac{4}{5}x \\ -3=1 \end{gathered}[/tex]

we got that

-3=1, it is false, which means there are no values that satisfy the equation, I n other words

the system has no solution

I hope this helps you

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