In order to determine a point that is part of the solution of the two given inequality, let's graph the two inequalities.
For both inequalities, they are already in a slope-intercept form y > mx + b where m = slope and b = the y-intercept.
For equation 1, y > x + 2, the y-intercept is 2 and slope is 1. Since the inequality is >, we will be using a broken line and the shade will be above the line.
The graph of inequality 1 is:
Moving on inequality 2, y > -2x - 7, the slope is -2 and the y-intercept is -7. Since the inequality symbol is >, we will be using a broken line on its border and the shade will be above the line.
The graph of inequality 2 is:
Combining the two graphs in one coordinate plane, we have:
The solution set of the given system of inequalities will be the common shaded area of both inequalities. There are infinite solutions for this.
We can get some coordinates from this common shaded area and this could be:
These coordinates can be (-3, 2), (-4, 3), (-2, 4), or (-2, 2).
We can also infer from the graph that the value of x is infinite however, the value of y must be greater than -1.
