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Sagot :
By arranging similar terms, we have
[tex]\begin{gathered} 6a+5a+2a-a-5 \\ \text{which gives} \\ 13a-a-5 \end{gathered}[/tex]since 13a minus a is 12a, the answer is
[tex]12a-5[/tex]which corresponds to option 2 from top to bottom
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