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Estimate the side length of a square that has a 9 cm long diagonal. ( The perimeter of a square is typically 2.8 times bigger than the diagonal)

Sagot :

The diagonal and two adjacent sides of the square form an isosceles right triangle.

By the Pythagorean theorem

[tex]\begin{gathered} s^2+s^2=9^2 \\ 2s^2=81 \\ s^2=\frac{81}{2} \\ s=\sqrt[]{\frac{81}{2}} \\ s=\frac{9}{\sqrt[]{2}} \\ s=6.36\text{ cm} \end{gathered}[/tex]

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