Answered

Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

You are helping with some repairs at home. You drop a hammer and it hits the floor at a speed of 12 feet per second. If the acceleration due to gravity (g) is 32 feet/second2, how far above the ground (h) was the hammer when you dropped it? Use the formula:A.8.5 feetB.1.0 footC.2.25 feetD.18.0 feet

You Are Helping With Some Repairs At Home You Drop A Hammer And It Hits The Floor At A Speed Of 12 Feet Per Second If The Acceleration Due To Gravity G Is 32 Fe class=

Sagot :

Solution

Step 1:

Given data:

[tex]\begin{gathered} v\text{ = 12} \\ \text{g = 32} \\ h\text{ = ?} \end{gathered}[/tex]

Step 2:

[tex]\begin{gathered} v\text{ = }\sqrt{2gh} \\ \\ 12\text{ = }\sqrt{2\times32\times h} \\ \\ 12\text{ = }\sqrt{64h} \\ \\ Take\text{ square of both sides} \\ \\ 12^2\text{ = \lparen}\sqrt{64h})^2 \\ \\ 144\text{ = 64h} \\ \\ h\text{ = }\frac{144}{64}\text{ = 2.25 feet} \end{gathered}[/tex]

Final answer

C. 2.25 feet

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.