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find an equation of a line with a slope of 6 and having the point (3,5) on the line

Find An Equation Of A Line With A Slope Of 6 And Having The Point 35 On The Line class=

Sagot :

Given:

The point (3,5)

The slope is 6.

To find the equation of the line:

Using the point-slope formula,

[tex]y-y_1=m(x-x_1)[/tex]

Substituting the point and slope, we get

[tex]\begin{gathered} y-5=6(x-3) \\ y-5=6x-18 \\ y=6x-18+5 \\ y=6x-13 \\ y-6x+13=0 \end{gathered}[/tex]

Hence, the equation of the line is,

[tex]y-6x+13=0[/tex]

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