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Sagot :
We need to first determine the expression of the line, for that we will use the point slope form, which is given below:
[tex]y-y_1=m\cdot(x-x_1)[/tex]Where m is the slope and (x1, y1) are the coordinates of a known point on the line.
[tex]\begin{gathered} y-2=-\frac{3}{4}(x-5) \\ y=-\frac{3}{4}(x-5)+2 \\ y=-\frac{3}{4}x+\frac{15}{4}+2 \\ y=-\frac{3}{4}x+\frac{15+8}{4} \\ y=-\frac{3}{4}x+\frac{23}{4} \end{gathered}[/tex]Now we need to graph it, for that we need two points. We already know the coordinates of one of them (5,2), now we need another, we can use the point for which x is equal to 0.
[tex]\begin{gathered} y=-\frac{3}{4}\cdot0+\frac{23}{4} \\ y=\frac{23}{4} \end{gathered}[/tex]Now we have (0, 23/4). We need to draw a line that passes
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