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Sagot :
[tex]\frac{5x^3-6x^2-8x\text{ +9}}{x^4+2x^3+x+1}[/tex]
We can no longer divide, since the exponent on the numerator is smaller than the exponent on the denominator
But we can present it in the form;
[tex]Q(x)\text{ +}\frac{R(x)}{d(x)}[/tex]In order to find the remainder and the quotient
[tex]^{}x^4+2x^3+x+1\sqrt[]{5x^{3\text{ }}-6x^2-8x+9}[/tex]Since, we can no longer divide it, then;
Q(x) =0
R(x) = 5x³ - 6x² -8x +9
d(x) = x⁴+2x³ + x + 1
[tex]0\text{ + }\frac{5x^3-6x^2-8x+9}{x^4+2x^3+x+1}[/tex]
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