Notice that, since we are rolling two dices, we are dealing with 2 independent events
Let's suppose that the numbers on each dice are 1,2,3,4.
Then, if we roll two dices, there are 16 possible pairs (in principle)
(1,1)
(1,2)
...
(1,4)
(2,1)
...
(4,4)
Each of those pairs is equally probably than the others
Know, we need to identify the pairs that add up 3:
(1,2) and (2,1) are the only possibilities
Finally, we obtain the probability:
[tex]P(x=3)=\frac{2}{16}=\frac{1}{8}=0.125[/tex]Which is none of the options.
Another possibility is that the dices are cubes:
So, the possible combinations that can be obtained by throwing 2 cubes are:
(1,1)...(1,6),(2,1),...(6,6) Which are 36 possible combinations
And there are only 2 combinations that add up to 3: (2,1),(1,2)
So, the probability of adding up 3 is:
[tex]P(x=3)=\frac{2}{36}=\frac{1}{16}=0.0625[/tex]