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Write an inequality for the word problem and answer the question about the inequality. Twice a number added to 6 is less than 23is 10 a possible solution.

Sagot :

Twice a number added to 6 is less than 23

[tex]2x+6<23[/tex]

is 10 a possible solution. ?

In order to answer this question, we must solve for x

[tex]\begin{gathered} 2x+6<23 \\ 2x+6-6<23-6 \\ 2x<17 \\ \frac{2x}{2}<\frac{17}{2} \\ x<\frac{17}{2} \\ x<8.5 \end{gathered}[/tex]

the solution is all numbers less than 8.5, therefore 10 is not a possible solution.