Answered

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Identify the equation without applying a rotation of axes.x squared +10xy+25y squared-2x-4y+10=0a. parabolab. ellipsec. hyperbolad. circle

Sagot :

Solution

We are given the equation

[tex]x^2+10xy+25y^2-2x-4y+10=0[/tex]

We will first simplify the equation

[tex]\begin{gathered} x^{2}+10xy+25y^{2}-2x-4y+10=0 \\ \left(x+5y\right)^2-2\left(x+y\right)+10=0 \\ (x+5y)^2=2(x+y)-10 \end{gathered}[/tex]

We draw the graph

From the graph, one can see that this is a rotated parabola

Correct answer is a Parabola

Option A

View image AryannaW74189
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