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Find the measure of the numbered angles in the rhombus (m1, m2, and m3).

Sagot :

The diagonals of a rhombus intersect at right angles. So, the m<1 is 90 degrees.

The diagonals of a rhombus bisect each vertex angle.

Therefore, the angle of vertex of 24 degree angle angle is 24x2=48.

The opposite angle of 48 degree angle is also 48 degrees. Since the angle is bisected by diagonal,m<2=24 degree.

The sum of opposite angles, 48+48=96.

The sum of other two equal opposite angles, 360-96=264.

The half of 264 is one angle, So, 264/2=132. Again <3=132/2=66.

m<1=90, m<3=66, m<2=24

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