Answered

Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Connect with a community of experts ready to help you find accurate solutions to your questions quickly and efficiently. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

At the bottom of the first hill, the 300 kg car is traveling 39.6 m/s. What is the kinetic energy of the car at this point? (ignore friction forces)

At The Bottom Of The First Hill The 300 Kg Car Is Traveling 396 Ms What Is The Kinetic Energy Of The Car At This Point Ignore Friction Forces class=

Sagot :

ANSWER:

1st option: 235,000 J

STEP-BY-STEP EXPLANATION:

Given:

Mass (m) = 300 kg

Speed (v) = 39.6 m/s

We can calculate the kinetic energy using the following formula:

[tex]\begin{gathered} E_K=\frac{1}{2}mv^2 \\ \text{ We replacing:} \\ E_K=\frac{1}{2}\cdot300\cdot39.6^2 \\ E_K=235224\cong235000\text{ J} \end{gathered}[/tex]

The kinetic energy is 235000 J.

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.