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Really need help with 11 and 12 just started learning this today and I don't quite understand it would really appreciate it

Really Need Help With 11 And 12 Just Started Learning This Today And I Dont Quite Understand It Would Really Appreciate It class=

Sagot :

11.

Given:

[tex]y=x^2[/tex]

Differentiate with respect to x, we get

[tex]\frac{dy}{dx}=2x[/tex]

The given point is (3,9)

Substitute x=3 in the derivative, we get

[tex]\frac{dy}{dx}=2\times\times3=6[/tex]

Hence the slope is 3.

12.

Given:

[tex]y=x^2+4[/tex]

Differentiate with respect to x, we get

[tex]\frac{dy}{dx}=2x+0[/tex]

The given point is (0,4)

Substitute x=0 in the derivative, we get

[tex]\frac{dy}{dx}=2(0)+0=0[/tex]

Hence the slope is 0.

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