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Sagot :
Given that the mass of the bike and cyclist is m = 75 kg and the velocity is v = 6 m/s. The height is h= 0 m
Mechanical energy is the sum of kinetic energy and potential energy.
The kinetic energy is given by the formula
[tex]\begin{gathered} K.E\text{. =}\frac{1}{2}mv^2 \\ =\frac{1}{2}\times75\times(6)^2 \\ =1350\text{ J} \end{gathered}[/tex]The potential energy is given by the formula,
[tex]\begin{gathered} P\mathrm{}E\mathrm{}=\text{mgh} \\ =75\times9.8\times0 \\ =0\text{ J} \end{gathered}[/tex]Here, g = 9.8 m/s^2 and is the acceleration due to gravity.
The mechanical energy will be
[tex]\begin{gathered} E=\text{ 1350 J+0 J} \\ =1350\text{ J} \end{gathered}[/tex]
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