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Sagot :
The values of α and β = 4/〖3x〗^2
A quadratic equation is a second-order polynomial equation in a single variable x
ax2+bx+c=0. with a ≠ 0
Given quadratic equation is 3x2 – 4x = 0
We have to alpha and beta from the given equation
We know that in the quadratic expression
α + β = -b/a. αβ = c/a.
from the equation expression
α + β = 4/〖3x〗^2
αβ = 0/3 ---- (1)
αβ = 0 ----- (2)
If we consider α = 0 from equation (2) then
α + β = 4/〖3x〗^2
β = 4/〖3x〗^2
If we consider β = 0 from equation (2) then
α + β = 4/〖3x〗^2
α = 4/〖3x〗^2
Therefore the values of α = β = 4/〖3x〗^2
To learn more about quadratic equations visit
https://brainly.com/question/17177510
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