The equation of a line is expressed as shown below;
[tex]y=mx+b[/tex]where:
• m is the ,slope, of the line
,• b is the ,y-intercept
Using two coordinate points on the line (0, -5) and (2, 0).
Determine the slope "m"
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{0-(-5)}{2-0} \\ m=\frac{0+5}{2} \\ m=\frac{5}{2} \end{gathered}[/tex]Determine the y-intercept "b"
The y-intercept of the line is the point where the line intersects the y-axis. According to the graph, the line intersects the y-axis at y = -5. Hence the y-intercept "b" is -5
Determine the required equation
Recall that y = mx + b, hence;
[tex]\begin{gathered} y=\frac{5}{2}x+(-5) \\ y=\frac{5}{2}x-5 \end{gathered}[/tex]This gives the required equation of the line.