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Sagot :
We will solve as follows:
*We will find the surface area by finding the areas of the smaller rectangles and adding them up, that is:
*Area of top rectangle:
[tex]A_1=5\cdot2\Rightarrow A_1=10[/tex]*Area of the two smaller rectangles on the side
[tex]A_2=2\cdot2\cdot3\Rightarrow A_2=12[/tex]*Area of the rectangle in the middle:
[tex]A_3=3\cdot5\Rightarrow A_3=15[/tex]*Area of the second rectangle [Bottom up]:
[tex]A_4=2\cdot5\Rightarrow A_4=10[/tex]*Area of the rectangle on the bottom:
[tex]A_5=3\cdot5\Rightarrow A_5=15[/tex]**Now, the surface area will be:
[tex]A_S=A_1+A_2+A_3+A_4+A_5\Rightarrow A_S=10+12+15+10+15[/tex][tex]\Rightarrow A_S=62[/tex]So, the surface area is 62 squared inches.
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