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Sagot :
Take into account that the general equation of a line can be written as follow:
[tex]y-y_o=m(x-x_o)[/tex]where m is the slope of the line and (xo,yo) are the coordinates of any point of the line.
In this case, you have:
m = -3
(xo,yo) = (-2,11)
Replace the previous values of the parameters into the general equation of the line and solve for y, as follow:
[tex]\begin{gathered} y-11=-3(x-(-2)) \\ y-11=-3(x+2) \\ y-11=-3x-6 \\ y=-3x-6+11 \\ y=-3x+5 \end{gathered}[/tex]Hence, the equation of the line is y = -3x + 5
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