Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
Given that angle θ1 is located in Quadrant II; and
[tex]\cos (\theta_1)=-\frac{12}{19}[/tex]Recall from trigonometric identity:
[tex]\begin{gathered} \cos \theta=\frac{\text{Adjacent}}{\text{Hypotenuse}} \\ \implies\text{Adjacent}=-12 \\ \text{Hypotenuse}=19 \end{gathered}[/tex]We find the value of Opposite using the Pythagoras theorem.
[tex]\begin{gathered} \text{Hyp}^2=\text{Opp}^2+\text{Adj}^2 \\ 19^2=\text{Opp}^2+(-12)^2 \\ \text{Opp}^2=19^2-(-12)^2 \\ \text{Opp}^2=361-144 \\ \text{Opp}^2=217 \\ \text{Opp}=\sqrt[]{217} \end{gathered}[/tex]Therefore, the value of sin(θ1) will be:
[tex]\begin{gathered} \sin (\theta_1)=\frac{\text{Opposite}}{\text{Hypotenuse}} \\ =\frac{\sqrt[]{217}}{19} \end{gathered}[/tex]Note: Sine is positive in Quadrant II.
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.
