Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Explore thousands of questions and answers from a knowledgeable community of experts on our user-friendly platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

With the wind, a plan flies 240 miles in 2 hours. Against the wind, the requires 3 hours to fly in the same distance. What is the rate of the wind?

Sagot :

Let x be the speed of the plane at not wind

Let y be the speed of the wind

Flying with the wind the effective speed is:

[tex]x+y[/tex]

Flying against the wind the effective speed is:

[tex]x-y[/tex]

Speed with the wind: use the distance and time given to calculate the spped:

[tex]\begin{gathered} \frac{240mi}{2h}=120mi/h \\ \\ x+y=120mi/h \end{gathered}[/tex]

Speed agains the wind: use the distance and time given to calculate the spped:

[tex]\begin{gathered} \frac{240mi}{3h}=80mi/h \\ \\ x-y=80mi/h \end{gathered}[/tex]

System of equations:

[tex]\begin{gathered} x+y=120 \\ x-y=80 \end{gathered}[/tex]

Add both equations:

Use 2x=200 to solve x:

[tex]\begin{gathered} 2x=200 \\ \\ x=\frac{200}{2} \\ \\ x=100 \end{gathered}[/tex]

Use x=100 to solve y:

[tex]\begin{gathered} x+y=120 \\ 100+y=120 \\ y=120-20 \\ \\ y=20 \end{gathered}[/tex]Then, the rate (speed) of the wind (y) is 20 mi/h

View image AftynZ33433