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(5,-10)(-9,10) what is the linear equation

Sagot :

In order to find the linear equation, let's use the slope-intercept form below:

[tex]y=mx+b[/tex]

Where m is the slope and b is the y-intercept.

Now, using the points (5, -10) and (-9, 10), we have:

[tex]\begin{gathered} y=mx+b \\ (5,-10)\colon \\ -10=5m+b \\ (-9,10)\colon \\ 10=-9m+b \end{gathered}[/tex]

Subtracting one equation by the other, we have:

[tex]\begin{gathered} -10-(10)=5m+b-(-9m+b) \\ -10-10=5m+b+9m-b \\ -20=14m \\ m=-\frac{20}{14}=-\frac{10}{7} \\ \\ -10=5m+b \\ -10=-\frac{50}{7}+b \\ b=-10+\frac{50}{7} \\ b=-\frac{20}{7} \end{gathered}[/tex]

So our linear equation is:

[tex]y=-\frac{10}{7}x-\frac{20}{7}[/tex]