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Sagot :
We will have the following:
We know that a standard deck of cards has 52 cards, composed of 4 sets, from which each set is composed of:
ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen and king.
Now, the probability of getting a 2 is:
[tex]p_1=\frac{4}{52}[/tex]And the probability of getting an odd number card [assuming the ace counts as a 1] will be:
[tex]p_2=\frac{20}{52}[/tex]So, the probability of the evens happening one after the other is:
[tex]\begin{gathered} p_3=p_1p_2\Rightarrow p_3=(\frac{4}{52})(\frac{20}{52}) \\ \\ \Rightarrow p_3=\frac{5}{169}\Rightarrow p_3=0.02958579882... \\ \\ \Rightarrow p_3\approx0.03 \end{gathered}[/tex]So, the probability is approximately 0.03.
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