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Sagot :
Given the following sum:
[tex]1\frac{1}{2}+7\frac{4}{5}[/tex]For each term we have (from mixed numbers to fractions):
[tex]\begin{gathered} 1\frac{1}{2}=\frac{1\cdot2+1}{2}=\frac{2+1}{2}=\frac{3}{2} \\ \\ 7\frac{4}{5}=\frac{7\cdot5+4}{5}=\frac{35+4}{5}=\frac{39}{5} \end{gathered}[/tex]Then:
[tex]1\frac{1}{2}+7\frac{4}{5}=\frac{3}{2}+\frac{39}{5}[/tex]Using the cross product method:
[tex]\begin{gathered} \frac{3}{2}+\frac{39}{5}=\frac{3\cdot5+39\cdot2}{2\cdot5}=\frac{15+78}{10}=\frac{93}{10} \\ \\ \therefore1\frac{1}{2}+7\frac{4}{5}=\frac{93}{10} \end{gathered}[/tex]In mixed form:
[tex]1\frac{1}{2}+7\frac{4}{5}=9\frac{3}{10}[/tex]
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