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Sagot :
Let x be the number of napkins Carla organized in 1 hour, and y be the number of napkins Karen organized in 1 hour, then we can set the following system of equations:
[tex]\begin{gathered} 3x+3y=90, \\ x=3y\text{.} \end{gathered}[/tex]Substituting x=3y in the first equation we get:
[tex]3(3y)+3y=90.[/tex]Solving for y we get:
[tex]\begin{gathered} 9y+3y=90, \\ 12y=90, \\ y=\frac{90}{12}, \\ y=7.5. \end{gathered}[/tex]Therefore, Karen organized 7.5 napkins each hour and Carla organized 7.5x3=22.5 napkins each hour.
Answer: Since Karen organized 7.5 napkins each hour, then it would take her
[tex]\frac{90}{7.5}=12[/tex]hours to do the 90 napkins.
Since Carla organized 22.5 napkins each hour, it would take her
[tex]\frac{90}{22.5}=4[/tex]hours to do the 90 napkins.
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