Answered

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Determine if the following system of equations has no solution , infinitely many solutions or exactly one solution .A = Infinitely Many Solutions B = One Solution C = No solutions

Determine If The Following System Of Equations Has No Solution Infinitely Many Solutions Or Exactly One Solution A Infinitely Many Solutions B One Solution C No class=

Sagot :

PROBLEM

x + 2y = -6

4x + 6y = -26

METHOD

Use substitution method

x + 2y = - 6 ........................................... 1

4x + 6y = -26 ......................................... 2

make x from equation 1 as subject of formula

x + 2y = -6

x = -6 - 2y

substitute x in equation 2

4(-6 - 2y) + 6y = -26

-24 - 8y + 6y = -26

-2y = -26 + 24

-2y = -2

y = -2/-2

y = 1

Now, solve for x

x = -6 - 2y

x = -6 -2(1)

x = -6 - 2

x = -8

( -8, 1) the system of equation has ONE SOLUTION

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