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The sum of two numbers is 41. The larger number is 23 more than the smallernumber. What are the numbers?

Sagot :

Given:

Let x be the smaller number and y be the larger number.

x + y = 41

y = x + 23

Substitute y=x + 23 into the first equation.

x + x+ 23 = 41

2x + 23 = 41

Subtract 23 from both-side of the equation.

2x = 41 - 23

2x =18

Divide both-side of the equation by 2.

x = 9

Substitute x = 9 into y = x + 23

y= 9 + 23 = 32

Hence, the numbers are 9 and 32.

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