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Sagot :
To find the x-intercept, we have to evaluate the expression when y = 0.
[tex]\begin{gathered} 2x+2y=2 \\ 2x+2\cdot0=2 \end{gathered}[/tex]Now, we solve for x.
[tex]2x+0=2[/tex]Then, we divide the equation by 2.
[tex]\begin{gathered} \frac{2x}{2}=\frac{2}{2} \\ x=1 \end{gathered}[/tex]This means the x-intercept is (1,0).
To find the y-intercept, we have to evaluate the expression when x = 0.
[tex]2\cdot0+2y=2[/tex]Now, we solve for y this time using the same process as before.
[tex]\begin{gathered} 0+2y=2 \\ \frac{2y}{2}=\frac{2}{2} \\ y=1 \end{gathered}[/tex]The y-intercept is (0,1).
Therefore, the x- and y-intercepts are (1,0) and (0,1), respectively.
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