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Find the image of F(6,-3) after the reflection across the line x=3

Sagot :

Recall that a reflection across the line x=k (with k a real number) transforms the point (x,y) as follows:

[tex](x,y)\rightarrow(2k-x,y).[/tex]

Therefore, the image of F(6,-3) after the reflection across the line x=3 is:

[tex](2\cdot3-6,-3)=(0,-3)\text{.}[/tex]

Answer: (0,-3).

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