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Sagot :
Given:
Length, L = 18 cm
Width, W = 9 cm
Asked: What is the perimeter of the piece of cardboard?
Solution:
[tex]\text{Perimeter of a rectangle = 2L + 2W}[/tex][tex]\begin{gathered} \text{Perimeter of a rectangle = 2(18) + 2}(9) \\ \text{Perimeter of a rectangle = 36 + }18 \\ \text{Perimeter of a rectangle = }54\text{ cm} \end{gathered}[/tex]ANSWER: 54 cm
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