Answered

Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

The population mean annual salary for a environmental compliance specialist is about 63,000A random sample of 30 specialist is drawn from the population.Assume sigma =6,300 What is the probability that the sample mean is less than 60,000

Sagot :

Given:

[tex]\mu=\text{ \$63000 ; n=30 ; }\sigma\text{=6300}[/tex][tex]P(\bar{x}<60000)=P(Z<\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt[]{n}}})[/tex][tex]P(\bar{x}<60000)=P(Z<\frac{60000-63000}{\frac{6300}{\sqrt[]{30}}})[/tex][tex]P(\bar{x}<60000)=P(Z<\frac{-3000}{\frac{6300}{\sqrt[]{30}}})[/tex][tex]P(\bar{x}<60000)=P(Z<-2.608)[/tex][tex]P(\bar{x}<60000)=P(Z<-2.61)[/tex]

From the standard normal table

[tex]P(Z<-2.61)=0.00453[/tex]

Therefore, 0.0045 is the probability of the given sample.

We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.