We have the following:
a.
we have that the perimeter of a figure is the sum of all the sides
[tex]\begin{gathered} p=\frac{3}{4}x+2x+\frac{3}{4}x+2x \\ p=\frac{11}{2}x \end{gathered}[/tex]
For the area:
[tex]\begin{gathered} A=A_1+A_2+A_3 \\ A=\frac{3}{4}x\cdot\frac{4}{3}x+\frac{1}{2}x\cdot\frac{1}{2}x+\frac{1}{4}x\cdot\frac{1}{4}x \\ A=x^2+\frac{x^2}{4}+\frac{x^2}{16} \\ A=\frac{21}{16}x^2 \end{gathered}[/tex]
b.
For perimeter
[tex]\begin{gathered} p=x+\frac{7}{4}x+x+\frac{7}{4}x \\ p=\frac{11}{2}x \end{gathered}[/tex]
For area:
[tex]\begin{gathered} A=A_1+A_2+A_3 \\ A=x\cdot\frac{1}{4}x+\frac{5}{4}x\cdot\frac{1}{4}x+x\cdot\frac{1}{4}x \\ A=\frac{13}{16}x^2 \end{gathered}[/tex]
