Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Get quick and reliable answers to your questions from a dedicated community of professionals on our platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Part (a);
[tex]\begin{gathered} \text{The area of the semi-circle with a radius of 5 yds;} \\ A=\pir^2^{} \\ \text{Foe a semi-circle (}\frac{1}{2}\text{ circle)} \\ \text{Area}=\frac{\pir^2}{2} \\ \text{Area}=\frac{3.14\times5^2}{2} \\ \text{Area}=\frac{78.5}{2} \\ \text{Area}=39.25yd^2 \\ \text{Area of the triangle=}\frac{1}{2}bh \\ b=\text{base (}15) \\ h=vertical\text{ height (10) that is radius x 2} \\ \text{Area}=\frac{1}{2}\times15\times10 \\ \text{Area}=75 \\ \text{Area of the entire figure=39.25 + 75} \\ \text{Area of the entire figure=114.25 yds}^2 \end{gathered}[/tex]Part (b);
[tex]\begin{gathered} \text{Area of the circle=}\pir^2 \\ \text{radius}=5\text{yds} \\ \text{Area}=3.14\times5^2 \\ \text{Area}=3.14\times25 \\ \text{Area}=78.5yd^2 \\ \text{Area of the triangle=}\frac{1}{2}\times bh \\ b=\text{base (16)} \\ h=\text{vertical height (16)} \\ \text{Area}=\frac{1}{2}\times16\times16 \\ \text{Area}=128yd^2 \\ Area\text{ of shaded region=Area of triangle-Area of circle} \\ \text{Area of shaded region=128-78.5} \\ \text{Area of shaded region=}49.5yd^2 \end{gathered}[/tex]
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.
