Answered

At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Get quick and reliable answers to your questions from a dedicated community of professionals on our platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

A chef uses a warming oven to maintain the temperature of food until all items are ready for plating. Potato croquettes, whose temperature is 200 C, are placed in the warming oven. The relationship between the core temperature of the potato in degrees Celsius, and the cooking time, t in minutes, is modelled by the equation 200 – T=180(0.94)t. If the chef needs to plate the entrée before the potato croquettes have a core temperature of 1400 C, how much time does he have?

A Chef Uses A Warming Oven To Maintain The Temperature Of Food Until All Items Are Ready For Plating Potato Croquettes Whose Temperature Is 200 C Are Placed In class=

Sagot :

Given

[tex]200-T=180(0.94)^t[/tex]

Solution

When T=140

[tex]\begin{gathered} 200-T=180(0.94)^{t} \\ \\ 200-140=180(0.94)^t \\ 60=180(0.94)^t \\ \\ 60=180\cdot\:0.94^t \\ Divide\text{ both side 180} \\ \frac{180\cdot \:0.94^t}{180}=\frac{60}{180} \\ \\ simplify \\ 0.94^t=\frac{1}{3} \end{gathered}[/tex]

Apply exponent rule

[tex]\begin{gathered} t\ln \left(0.94\right)=\ln \left(\frac{1}{3}\right) \\ \\ t=-\frac{\ln \left(3\right)}{\ln \left(0.94\right)} \\ \\ \\ t=17.7552 \end{gathered}[/tex]

The final answer

t =1 7.7552years

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.