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Sagot :
SOLUTION:
We want to find the probability that;
[tex]P(1st\text{ }Purple\text{ }and\text{ }2nd\text{ }Not\text{ }Purple)[/tex][tex]\begin{gathered} P(1st\text{ }Purple)=\frac{5}{10}=\frac{1}{2} \\ P(2nd\text{ not purple\rparen}=\frac{5}{9} \end{gathered}[/tex]Thus;
[tex]P(1st\text{ }purple\text{ }&\text{ }2nd\text{ }not\text{ }purple)=\frac{1}{2}\times\frac{5}{9}=\frac{5}{18}[/tex]Thus, the answer is;
[tex]\frac{5}{18}[/tex]
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