Answered

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Can someone help me with this geometry question? My instructor says I am wrong can you help me figure it out? I will provide you with all the information I can

Can Someone Help Me With This Geometry Question My Instructor Says I Am Wrong Can You Help Me Figure It Out I Will Provide You With All The Information I Can class=

Sagot :

Solution

The different orders is given as

[tex]_nP_r=_{14}P_3[/tex]

This is simplified as

[tex]\begin{gathered} _{14}P_3=\frac{14!}{(14-3)!} \\ =\frac{14!}{11!} \end{gathered}[/tex]

This further give

[tex]\frac{14!}{11!}=\frac{14\times13\times12\times11!}{11!}=2184[/tex]

Therefore the answer is 2184

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